Hydraulic Power Formulas
kW = bar × L/min / 600HP = psi × GPM / 1714Nm = cm³/rev × bar / (20π)
Example: 2,320 psi (160 bar) × 10.6 GPM (40 L/min) → 14.3 HP (10.7 kW) hydraulic power; with 88% efficiency the electric motor needs about 16 HP (12.1 kW).
Hydraulic Power Chart
| Pressure | 5 GPM | 10 GPM | 20 GPM | 30 GPM |
|---|---|---|---|---|
| 1,000 psi | 2.9 HP | 5.8 HP | 11.7 HP | 17.5 HP |
| 1,500 psi | 4.4 HP | 8.8 HP | 17.5 HP | 26.3 HP |
| 2,000 psi | 5.8 HP | 11.7 HP | 23.3 HP | 35.0 HP |
| 2,500 psi | 7.3 HP | 14.6 HP | 29.2 HP | 43.8 HP |
| 3,000 psi | 8.8 HP | 17.5 HP | 35.0 HP | 52.5 HP |
Hydraulic Motor Power – FAQ
How do you calculate hydraulic power?
P (kW) = p (bar) × Q (L/min) / 600; in US units HP = psi × GPM / 1714. Divide by overall efficiency (0.85–0.9) for motor power.
How do you calculate hydraulic motor torque?
Torque (Nm) = displacement (cm³/rev) × Δp (bar) / (20π); in US units lbf·in = displacement (in³/rev) × psi / (2π).