Optimum Diameter of Pipe Formula
The optimum inner diameter of a hydraulic pipe is the one that keeps oil velocity inside the recommended range for the line type: small enough to limit cost and weight, large enough to limit pressure loss and heat.
d = √(4 × Q / (π × v))d (in) = √(0.408 × GPM / v (ft/s))
Recommended Velocities
| Line | m/s | ft/s |
|---|---|---|
| Suction | 0.5 – 1.5 | 2 – 4 |
| Pressure | 3 – 6 | 10 – 20 |
| Return | 2 – 4 | 7 – 13 |
Pipe Inner Diameter by Flow
| Flow | Suction @1 m/s | Pressure @4 m/s | Return @3 m/s |
|---|---|---|---|
| 10 L/min (2.6 GPM) | 14.6 mm | 7.3 mm | 8.4 mm |
| 20 L/min (5.3 GPM) | 20.6 mm | 10.3 mm | 11.9 mm |
| 40 L/min (10.6 GPM) | 29.1 mm | 14.6 mm | 16.8 mm |
| 60 L/min (15.9 GPM) | 35.7 mm | 17.8 mm | 20.6 mm |
| 100 L/min (26.4 GPM) | 46.1 mm | 23.0 mm | 26.6 mm |
| 150 L/min (39.6 GPM) | 56.4 mm | 28.2 mm | 32.6 mm |
| 200 L/min (52.8 GPM) | 65.1 mm | 32.6 mm | 37.6 mm |
Hydraulic Pipe Size – FAQ
How do you calculate hydraulic pipe size?
d = √(4Q / (π × v)). With Q in m³/s and v in m/s the result is in metres. In US units: d (in) = √(0.408 × Q (GPM) / v (ft/s)).
What velocity should I use?
Suction lines 0.5–1.5 m/s (2–4 ft/s), pressure lines 3–6 m/s (10–20 ft/s), return lines 2–4 m/s (7–13 ft/s).
What is the optimum pipe diameter formula?
For hydraulic lines the optimum diameter is the one that keeps velocity within the recommended range for the line type, balancing pressure loss against cost; use d = √(4Q/(πv)) with the recommended v.